How many moles of oxygen are formed when 58.6 g of KNO₃ decomposes according to the following reaction? The molar mass of KNO₃ is 101.11 g mol^-1. 4KNO₃(s) → 2K₂O(s) + 2N₂(g) + 5O₂(g) A) 0.290 mol O₂ B) 0.580 mol O₂ C) 18.5 mol O₂ D) 0.724 mol O₂ E) 1.73 mol O₂

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Quizplus · Accepted Answer

1 mol of KNO₃ produces 5 mol of O₂ Therefore, 58.6 g of KNO₃ is equal to (58.6/101.11) = 0.579 mol of KNO₃ Using stoichiometry of the reaction, 4 KNO₃ → 5 O₂ 0.579 mol → (5/4) x 0.579 mol = 0.724 mol of O₂. Therefore, the answer is D.

How Many Moles of Oxygen Are Formed When 58