According to the following balanced reaction, how many moles of KO are required to exactly react with 5.44 moles of H₂O? 4KO(s) + 2H₂O(l) → 4KOH(s) + O₂(g) A) 2.72 moles KO B) 16.7 moles KO C) 10.9 moles KO D) 8.33 moles KO E) 4.87 moles KO

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From the balanced equation, we can see that 4 moles of KO reacts with 2 moles of H₂O. Thus, the ratio of moles of KO to moles of H₂O is 4:2 or 2:1. Therefore, to react with 5.44 moles of H₂O, we would need 2.72 moles of KO. However, since a balanced reaction must have integer coefficients, the closest integer ratio of KO to H₂O is actually 4:2 or 2:1. Therefore, we need twice the amount of KO, which is 2 x 5.44 = 10.88, or approximately 10.9 moles of KO to react with 5.44 moles of H₂O.

According to the Following Balanced Reaction, How Many Moles of KO