How many grams of Li₃N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s)+ N₂(g)→ 2 Li₃N(s) A) 18.3 g Li₃N B) 20.3 g Li₃N C) 58.3 g Li₃N D) 61.0 g Li₃N E) 15.1 g Li₃N

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The Answer of How many grams of Li₃N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s)+ N₂(g)→ 2 Li₃N(s) A) 18.3 g Li₃N B) 20.3 g Li₃N C) 58.3 g Li₃N D) 61.0 g Li₃N E) 15.1 g Li₃N

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How Many Grams of Li₃N Can Be Formed from 1