How many moles of oxygen are formed when 58.6 g of KNO₃ decomposes according to the following reaction? The molar mass of KNO₃ is 101.11 g/mol. 4 KNO₃(s)→ 2 K₂O(s)+ 2 N₂(g)+ 5 O₂(g) A) 0.290 mol O₂ B) 0.580 mol O₂ C) 18.5 mol O₂ D) 0.724 mol O₂ E) 1.73 mol O₂

Question

Quizplus · Accepted Answer

First, we need to find the number of moles of KNO₃ using its molar mass: 58.6 g KNO₃ x (1 mol KNO₃/101.11 g KNO₃) = 0.5797 mol KNO₃ Since the ratio of KNO₃ to O₂ is 4:5, we can use stoichiometry to find the number of moles of O₂ that will form: 0.5797 mol KNO₃ x (5 mol O₂/4 mol KNO₃) = 0.7241 mol O₂ Therefore, the answer is D, 0.724 mol O₂.

How Many Moles of Oxygen Are Formed When 58