What volume (in mL) of a 0.0887 mol L^-1 MgF₂ solution is needed to make 275.0 mL of a 0.0224 mol L^-1 MgF₂solution?

Question

Quizplus · Accepted Answer

This is a simple mole-to-mole ratio problem. We need to use the equation:

moles = concentration × volume

To find the volume of the 0.0887 mol MgF solution, we can rearrange the equation like this:

volume = moles / concentration

Then plug in the values we know:

volume = 0.0224 mol / 0.0887 mol/L
volume = 0.2524 L or 252.4 mL

So we need 252.4 mL of the 0.0887 mol MgF solution, which is not one of the answer choices. However, we can use the mole-to-mole ratio to find how much of the 0.0887 mol MgF solution contains 0.0224 mol MgF.

0.0224 mol MgF × (1 L / 0.0887 mol MgF) = 0.2524 L or 252.4 mL

Therefore, we need the same volume of the 0.0887 mol MgF solution as the volume of the 0.0224 mol MgF solution, which is 252.4 mL. To get 275.0 mL of the 0.0224 mol MgF solution, we need to use the following equation:

volume of 0.0887 mol MgF solution = (0.0224 mol / 0.0887 mol/L) × 275.0 mL
volume of 0.0887 mol MgF solution = 69.4 mL

So the answer is D.

What Volume (In ML) of a 0