According to the following reaction, what mass of PbCl₂ can form from 235 mL of a 0.110 mol L^-1 KCl solution? Assume that there is excess Pb(NO₃)₂. 2KCl(aq) + Pb(NO₃)₂(aq) → PbCl₂(s) + 2KNO₃(aq)

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The reaction shows that 2 moles of KCl produce 1 mole of PbCl2. Calculate moles of KCl: 0.235 L * 0.110 mol/L = 0.02585 mol KCl. Moles of PbCl2 = 0.02585 mol KCl / 2 = 0.012925 mol PbCl2. Molar mass of PbCl2 = 278.1 g/mol. Mass of PbCl2 = 0.012925 mol * 278.1 g/mol = 3.59 g.

According to the Following Reaction, What Mass of PbCl2 Can

According to the Following Reaction, What Mass of PbCl₂ Can