How many chloride ions are present in 65.5 mL of 0.210 mol L^-1 AlCl₃ solution?

Question

Quizplus · Accepted Answer

We can use the formula:

moles = concentration x volume

to find the number of moles of AlCl3 present in the solution:

moles AlCl3 = 0.210 mol/L x 0.0655 L
moles AlCl3 = 0.013755

Since AlCl3 dissociates into 4 ions in solution (1 Al3+ ion and 3 Cl- ions), we can find the number of chloride ions present by multiplying the number of moles of AlCl3 by 3:

moles Cl- = 3 x 0.013755
moles Cl- = 0.041265

Finally, we can convert the number of moles of Cl- to the number of chloride ions by using Avogadro's number (6.022 x 10^23 ions per mole):

number of chloride ions = 0.041265 mol x 6.022 x 10^23 ions/mol
number of chloride ions = 2.48 x 10^22

Therefore, the answer is (C) 2.48 x 10^22 chloride ions.

How Many Chloride Ions Are Present in 65