What volume of 0.305 mol L^-1 AgNO₃ is required to react exactly with 155.0 mL of 0.274 mol L^-1 Na₂SO₄ solution? Hint: You will want to write a balanced reaction.

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Quizplus · Accepted Answer

The balanced reaction is: 2AgNO₃ + Na₂SO₄ → Ag₂SO₄ + 2NaNO₃. The moles of Na₂SO₄ are 0.155 L * 0.274 mol/L = 0.04247 mol. Since the stoichiometry is 2:1, moles of AgNO₃ needed are 2 * 0.04247 mol = 0.08494 mol. The volume of AgNO₃ is 0.08494 mol / 0.305 mol/L = 0.278 L or 278 mL.

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