A 2.25- g sample of magnesium nitrate, Mg(NO₃)₂, contains mol of this compound. A) 0.0261 B) 65.8 C) 0.0152 D) 148.3 E) 38.4

Question

Quizplus · Accepted Answer

To find the number of moles of Mg(NO3)2 in the sample, we need to divide the mass of the compound by its molar mass. The molar mass of Mg(NO3)2 can be calculated by adding the atomic masses of magnesium (Mg), nitrogen (N), and three oxygen (O) atoms present in the formula:

Mg(NO3)2 molar mass = Mg molar mass + N molar mass + 3 x O molar mass
Mg(NO3)2 molar mass = 24.31 g/mol + 14.01 g/mol + 3 x 16.00 g/mol
Mg(NO3)2 molar mass = 148.31 g/mol

Now, we can calculate the number of moles of Mg(NO3)2 in the sample:

moles = mass / molar mass
moles = 2.25 g / 148.31 g/mol
moles = 0.0152 mol

Therefore, the best choice is C, which corresponds to 0.0152.

A 225- G Sample of Magnesium Nitrate, Mg(NO3)2, Contains Mol of of This

A 225- G Sample of Magnesium Nitrate, Mg(NO₃)₂, Contains Mol of of This