How many grams of hydrogen are in 46 g of CH₄O? A) 1.5 B) 5.8 C) 184 D) 2.8 E) 0.36

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First, we need to determine the empirical formula of the compound CH₄O. To do this, we need to find the moles of each element present. - Carbon (C): 1 mole - Hydrogen (H): 14/1 = 14 moles - Sulfur (S): 1 + 1 = 2 moles - Boron (B): 14/4 = 3.5 moles - Oxygen (O): 1 mole To find the simplest whole-number ratio of these moles, we divide each by the smallest number of moles (which is 1 mole in this case): - C: 1/1 = 1 - H: 14/14 = 1 - S: 2/1 = 2 - B: 3.5/1 = 3.5 - O: 1/1 = 1 So the empirical formula is CS2B7H14O. Next, we need to calculate the molar mass of this empirical formula: (1 x 12.01) + (2 x 32.06) + (7 x 10.81) + (14 x 1.01) = 246.97 g/mol Now we can use the molar mass of the empirical formula to calculate the number of moles of the entire compound (46 g): 46 g / 246.97 g/mol = 0.186 moles Finally, we can use the mole ratio from the empirical formula to calculate the number of moles of hydrogen: 1 mole of compound contains 14 moles of hydrogen (from the empirical formula) 0.186 moles of compound contain (0.186 moles)(14 moles of H/1 mole of compound) = 2.604 moles of hydrogen Now we just need to convert moles of hydrogen to grams: 2.604 moles of H x 1.01 g/mol = 2.63 g Therefore, the answer is B (5.8 g).

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