A 22.5- g sample of ammonium carbonate contains mol of ammonium ions.
A) 2.14
B) 0.234
C) 0.468
D) 3.47
E) 0.288

Question

Quizplus · Accepted Answer

First, we need to find the molar mass of ammonium carbonate (NH4)2CO3.

Molar mass of (NH4)2CO3 = 2(14.01 g/mol) + 1(12.01 g/mol) + 3(16.00 g/mol) = 96.09 g/mol

Next, we need to find the number of moles of ammonium carbonate in the sample:

moles of (NH4)2CO3 = 22.5 g / 96.09 g/mol = 0.234 mol

Since there are 2 ammonium ions (NH4+) in every molecule of (NH4)2CO3, the number of moles of ammonium ions is:

moles of NH4+ = 2 x moles of (NH4)2CO3 = 2 x 0.234 mol = 0.468 mol

Therefore, the answer is C) 0.468.

A 225- G Sample of Ammonium Carbonate Contains Mol of Ammonium