The rate of disappearance of HBr in the gas phase reaction 2HBr (g) →H₂(g) + Br₂(g)
Is 0.301 M s^-¹at 150°C. The rate of appearance of Br₂is M s^-¹.

Question

The rate of disappearance of HBr in the gas phase reaction 2HBr (g) →H₂(g) + Br₂(g) Is 0.301 M s^-¹at 150°C. The rate of appearance of Br₂is M s^-¹.

Quizplus · Accepted Answer

The rate of appearance of Br₂ is half the rate of disappearance of HBr because the stoichiometry of the reaction shows that 2 moles of HBr produce 1 mole of Br₂. Therefore, the rate is 0.301 M s⁻¹ / 2 = 0.1505 M s⁻¹, which rounds to 0.151 M s⁻¹.

The Rate of Disappearance of HBr in the Gas Phase