A 0.325 L flask filled with gas at 0.914 atm and 19 °C contains mol of gas. A) 1.48 × 10^-² B) 12.4 C) 80.7 D) 1.24 × 10^-² E) 9.42

Name: A 0.325 L flask filled with gas at 0.914 atm and 19 °C contains mol of gas. A) 1.48 × 10 - 2 B) 12.4 C) 80.7 D) 1.24 × 10 - 2 E) 9.42
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Question

Quizplus · Accepted Answer

Using the ideal gas law PV = nRT, where P = 0.914 atm, V = 0.325 L, R = 0.0821 L·atm/mol·K, and T = 19°C (292 K), we solve for n (moles of gas): n = PV/RT = (0.914 * 0.325) / (0.0821 * 292) = 1.24 × 10^-2 mol.

A 0325 L Flask Filled with Gas at 0