Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, and calculate the standard cell potential.
Pb2+(aq) + 2 e- ? Pb(s)
E° = -0.126 V
Fe3+(aq) + e- ? Fe2+(s)
E° = +0.771 V
A) Pb2+(aq) + 2 Fe2+(s) ? Pb(s) + 2 Fe3+(aq) ; = +0.897 V
B) Pb2+(aq) + Fe2+(s) ? Pb(s) + Fe3+(aq) ; = +0.645 V
C) Pb(s) + 2 Fe3+(aq) ? Pb2+(aq) + 2 Fe2+(s) ; = +1.416 V
D) Pb(s) + 2 Fe3+(aq) ? Pb2+(aq) + 2 Fe2+(s) ; = +0.897 V
E) Pb(s) + Fe3+(aq) ? Pb2+(aq) + Fe2+(s) ; = +0.645 V
Correct Answer:
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