The concentration of calcium carbonate in a saturated aqueous solution at 25°C is $6.71 \times 10 ^ { - 5 }$ M. What is the K_sp of this sparingly soluble salt?

Question

Quizplus · Accepted Answer

The solubility product $K_{sp}$ for calcium carbonate, $CaCO_3$, is calculated using the formula $K_{sp} = [Ca^{2+}][CO_3^{2-}]$. Since the concentration of $CaCO_3$ is $6.71 \times 10^{-5}$ M, both $Ca^{2+}$ and $CO_3^{2-}$ ions will have the same concentration in a saturated solution. Therefore, $K_{sp} = (6.71 \times 10^{-5})^2 = 4.5 \times 10^{-9}$.

The Concentration of Calcium Carbonate in a Saturated Aqueous Solution 6.71×10−56.71 \times 10 ^ { - 5 }6.71×10−5

The Concentration of Calcium Carbonate in a Saturated Aqueous Solution $6.71 \times 10 ^ { - 5 }$