At 800 K, the equilibrium constant, K_p, for the following reaction is 3.2 × 10^-7. 2 H₂S(g) $\rightleftharpoons$ 2 H₂(g) + S₂(g)
A reaction vessel at 800 K initially contains 3.00 atm of H₂S. If the reaction is allowed to equilibrate, what is the equilibrium pressure of S₂?

Question

At 800 K, the equilibrium constant, K_p, for the following reaction is 3.2 × 10^-7. 2 H₂S(g)

\rightleftharpoons

2 H₂(g) + S₂(g)
A reaction vessel at 800 K initially contains 3.00 atm of H₂S. If the reaction is allowed to equilibrate, what is the equilibrium pressure of S₂?

Quizplus · Accepted Answer

The Answer of At 800 K, the equilibrium constant, K_p, for the following reaction is 3.2 × 10^-7. 2 H₂S(g) $\rightleftharpoons$ 2 H₂(g) + S₂(g) A reaction vessel at 800 K initially contains 3.00 atm of H₂S. If the reaction is allowed to equilibrate, what is the equilibrium pressure of S₂?

At 800 K, the Equilibrium Constant, Kp, for the Following ⇌\rightleftharpoons⇌

At 800 K, the Equilibrium Constant, K_p, for the Following $\rightleftharpoons$