Consider the reaction H₂ + I₂ $\rightleftharpoons$ 2HI for which K_c = 44.0 at a high temperature. If an equimolar mixture of reactants gives the concentration of the product to be 0.50 M at equilibrium, determine the equilibrium concentration of the hydrogen.

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The equilibrium constant expression for the reaction is:K_c = [HI]^2 / [H₂][I₂]At equilibrium, the concentration of HI is 0.50 M. Since the initial concentrations of H₂ and I₂ are equal, let x be the change in concentration of each reactant at equilibrium. Then, the equilibrium concentrations of H₂ and I₂ are (0.50 - x) M.Substituting these concentrations into the equilibrium constant expression, we get:44.0 = (0.50)^2 / (0.50 - x)^2Solving for x, we get:x = 0.075 MTherefore, the equilibrium concentration of hydrogen is:[H₂] = 0.50 - x = 0.50 - 0.075 = 0.425 M

Consider the Reaction H2 + I2 ⇌\rightleftharpoons⇌ 2HI for Which Kc = 44

Consider the Reaction H₂ + I₂ $\rightleftharpoons$ 2HI for Which K_c = 44