If K_c = 0.124 for A₂ + 2B $\rightleftharpoons$ 2AB, what is the value of K_c for the reaction 4AB $\rightleftharpoons$ 2A₂ + 4B?

Question

Quizplus · Accepted Answer

The given reaction is the reverse of the original reaction and doubled. The equilibrium constant for the reverse reaction is the reciprocal of the original Kc, and when the reaction is doubled, the equilibrium constant is squared. Therefore, Kc for the new reaction is (1/0.124)^2 = 65.0.

If Kc = 0 ⇌\rightleftharpoons⇌ 2AB, What Is the Value of Kc for the Reaction

If K_c = 0 $\rightleftharpoons$ 2AB, What Is the Value of K_c for the Reaction