Calcium carbonate,or limestone,is relatively insoluble in water.At 25 °C,only 5.8 mg will dissolve in 1.0 liter of water.What volume of water is needed to dissolve 5.0 g of calcium carbonate? A) 4.6 × 10^-3 L B) 3.0 × 10^-2 L C) 1.4 × 10² L D) 3.4 × 10² L E) 8.6 × 10² L

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Quizplus · Accepted Answer

To dissolve 5.0 g (5000 mg) of calcium carbonate, you need 5000 mg / 5.8 mg/L = 862.07 L, which is approximately 8.6 × 10^2 L.

Calcium Carbonate,or Limestone,is Relatively Insoluble in Water