A gas with pressure of 5.0 atm is compressed at constant temperature from 10.0 L to 2.0 L.What is the pressure of the gas after it is compressed?

Question

Quizplus · Accepted Answer

According to Boyle's Law, $P_1V_1 = P_2V_2$ for a gas at constant temperature, where $P_1$ and $V_1$ are the initial pressure and volume, and $P_2$ and $V_2$ are the final pressure and volume. Given $P_1 = 5.0$ atm, $V_1 = 10.0$ L, and $V_2 = 2.0$ L, solving for $P_2$ gives $P_2 = \frac{P_1V_1}{V_2} = \frac{5.0 \times 10.0}{2.0} = 25$ atm.

A Gas with Pressure of 5