A proton with mass 1.67 * 10^-²⁷kg moves with a speed of 0.800c in an accelerator. What is its relativistic momentum? (c = 3.00*10⁸ m/s) A) 2.40 *10^-¹⁹ kg.m/s B) 6.68 *10^-¹⁹ kg.m/s C) 0.530 *10^-¹⁹ kg.m/s D) 3.76 *10^-¹⁹ kg.m/s

Question

Quizplus · Accepted Answer

The relativistic momentum is calculated using the formula p = γmv, where γ = 1/√(1-v²/c²). For v = 0.800c, γ ≈ 1.667. Thus, p = 1.667 * 1.67 x 10^-27 kg * 0.800 * 3.00 x 10^8 m/s ≈ 6.68 x 10^-19 kg·m/s.

A Proton with Mass 1