If a proton with mass 1.67 *10^-²⁷ kg moves in an accelerator such that its total energy is two times its rest energy, what is its speed? (c = 3.00 * 10⁸ m/s) A) 1.00 * 10⁸ m/s B) 2.83 * 10⁸ m/s C) 1.41 * 10⁸ m/s D) 2.60 * 10⁸ m/s

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Quizplus · Accepted Answer

The total energy being twice the rest energy implies that the kinetic energy is equal to the rest energy. Using the relativistic energy-momentum relation, the speed can be calculated as v = c√(1 - (1/2)²) = 2.60 × 10⁸ m/s.

If a Proton with Mass 1