A 20-N crate starting at rest slides down a rough 5.0-m long ramp, inclined at 25 $\degree$ with the horizontal. 30 J of energy is lost to friction. What will be the speed of the crate at the bottom of the incline?
A) 0.98 m/s
B) 2.1 m/s
C) 3.5 m/s
D) 4.7 m/s

Question

Quizplus · Accepted Answer

The gravitational potential energy lost is mgh = 20 N * 5 m * sin(25°). Subtract the 30 J lost to friction to find the kinetic energy at the bottom, then solve for speed using KE = 0.5 * m * v^2.

A 20-N Crate Starting at Rest Slides Down a Rough °\degree°

A 20-N Crate Starting at Rest Slides Down a Rough $\degree$