Consider the reaction: 2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O. How many grams of Al₂(SO₄)₃ are generated when 152 g of H₂SO₄ reacts?

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Quizplus · Accepted Answer

To solve this, first, we need to correct the chemical formulas from the given reaction: $2 \text{Al(OH)}_3 + 3 \text{H}_2\text{SO}_4 \rightarrow \text{Al}_2(\text{SO}_4)_3 + 6 \text{H}_2\text{O}$. The molar mass of $\text{H}_2\text{SO}_4$ is approximately 98 g/mol, so 152 g corresponds to about 1.55 moles. According to the reaction, 3 moles of $\text{H}_2\text{SO}_4$ produce 1 mole of $\text{Al}_2(\text{SO}_4)_3$, so 1.55 moles will produce about 0.517 moles of $\text{Al}_2(\text{SO}_4)_3$. The molar mass of $\text{Al}_2(\text{SO}_4)_3$ is approximately 342 g/mol, so 0.517 moles correspond to about 177 g.

Consider the Reaction: 2 Al(OH)3 + 3 H2SO4 → Al2(SO4)3

Consider the Reaction: 2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃