Consider the following equation: HCl (aq) + NaOH (aq) $\rightarrow$ H₂O (l) + NaCl (aq)
If 0.25 moles of sodium hydroxide completely react with hydrochloric acid,how many moles of water will be made?

Question

Consider the following equation: HCl (aq)+ NaOH (aq)$\rightarrow$ H₂O (l)+ NaCl (aq) If 0.25 moles of sodium hydroxide completely react with hydrochloric acid,how many moles of water will be made?

Quizplus · Accepted Answer

The balanced chemical equation for the reaction between HCl and NaOH is HCl + NaOH → H2O + NaCl. This shows a 1:1 mole ratio between NaOH and H2O. Therefore, if 0.25 moles of NaOH react completely, 0.25 moles of water will be produced.

Consider the Following Equation: HCl (Aq)+ NaOH (Aq) →\rightarrow→ H2O (L)+ NaCl (Aq) If 0

Consider the Following Equation: HCl (Aq)+ NaOH (Aq) $\rightarrow$ H₂O (L)+ NaCl (Aq)
If 0