When the potential difference between the plates of an ideal air-filled parallel plate capacitor is 35 V, the electric field between the plates has a strength of 750 V/m. If the plate area is 4.0 × 10^-² m², what is the capacitance of this capacitor? (?₀ = 8.85 × 10^-12C²/N ? m²)

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor is given by $ C = \frac{\varepsilon_0 A}{d} $. The distance $ d $ between the plates can be found using $ V = Ed $, giving $ d = \frac{V}{E} = \frac{35}{750} $. Substituting the values, $ C = \frac{8.85 \times 10^{-12} \times 4.0 \times 10^{-2}}{35/750} = 7.6 \times 10^{-12} $ F.

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