It requires 0.30 kJ of work to fully drive a stake into the ground. If the average resistive force on the stake by the ground is $828 \mathrm {~N} ,$ how long is the stake?
A)0.36 m
B)0.23 m
C)0.31 m
D)0.41 m

Question

Quizplus · Accepted Answer

Work done = Force × Distance$0.30 \times 10^3 \mathrm{~J} = 828 \mathrm{~N} \times d$$d = 0.36 \mathrm{~m}$

It Requires 0 828 N,828 \mathrm {~N} ,828 N, How Long Is the Stake? A)0

It Requires 0 $828 \mathrm {~N} ,$ How Long Is the Stake?
A)0