A 1200-kg cannon suddenly fires a $100 - \mathrm { kg }$ cannonball at $35 \mathrm {~m} / \mathrm { s }$ What is the recoil speed of the cannon? Assume that frictional forces are negligible and the cannon is fired horizontally.

Question

Quizplus · Accepted Answer

Using conservation of momentum: $ m_1v_1 = m_2v_2 $. Here, $ m_1 = 100 \, \text{kg} $, $ v_1 = 35 \, \text{m/s} $, $ m_2 = 1200 \, \text{kg} $. Solving for $ v_2 $ gives $ v_2 = \frac{100 \times 35}{1200} = 2.9 \, \text{m/s} $.

A 1200-Kg Cannon Suddenly Fires A 100−kg100 - \mathrm { kg }100−kg

A 1200-Kg Cannon Suddenly Fires A $100 - \mathrm { kg }$