A 0.140-kg baseball is thrown with a velocity of $27.1 \mathrm {~m} / \mathrm { s }$ It is struck by the bat with an average force of 5000 N, which results in a velocity of 37.0 m/s in the opposite direction from the original velocity. How long were the bat and ball in contact?

Question

Quizplus · Accepted Answer

Impulse = change in momentum$J = mv_f - mv_i$$5000 N \cdot t = (0.140 kg)(37.0 m/s) - (0.140 kg)(-27.1 m/s)$$t = 1.79 \times 10^{-3} s$

A 0140-Kg Baseball Is Thrown with a Velocity Of Of 27.1