In E. coli, a P1 generalized transduction was carried out using a donor strain of ara⁺ leu⁺ ilvH⁺ genotype. The recipient strain was ara^- leu^- ilvH^-. 381 ara⁺ transductants were first recovered and then the remaining genotypes of these 381 were determined and the results are shown below: $$\begin{array} { l } \mathrm { ara } ^ { + } \text {leu}^-{ ilvH }^- \quad = 32 \ \mathrm { ara } ^ { + } \mathrm { leu } ^ { + } i \mathrm { lv } \mathrm { H } ^ { - } = 9 \ \mathrm { ara } ^ { + } \operatorname { leu }^- i \mathrm { lv } \mathrm { H } ^ { + } = 0 \ \mathrm { ara } ^ { + } \mathrm { leu } ^ { + } \mathrm { llv } \mathrm { H } ^ { + } \quad = 340 \ \end{array}$$ Which gene is in the middle?

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The Answer of In E. coli, a P1 generalized transduction was carried out using a donor strain of ara⁺ leu⁺ ilvH⁺ genotype. The recipient strain was ara^- leu^- ilvH^-. 381 ara⁺ transductants were first recovered and then the remaining genotypes of these 381 were determined and the results are shown below: $$\begin{array} { l } \mathrm { ara } ^ { + } \text {leu}^-{ ilvH }^- \quad = 32 \ \mathrm { ara } ^ { + } \mathrm { leu } ^ { + } i \mathrm { lv } \mathrm { H } ^ { - } = 9 \ \mathrm { ara } ^ { + } \operatorname { leu }^- i \mathrm { lv } \mathrm { H } ^ { + } = 0 \ \mathrm { ara } ^ { + } \mathrm { leu } ^ { + } \mathrm { llv } \mathrm { H } ^ { + } \quad = 340 \ \end{array}$$ Which gene is in the middle?

In E Coli, a P1 Generalized Transduction Was Carried Out Using