Suppose that in a population the frequency of a particular recessive condition is 1/400. Assume the presence of only a dominant allele (A) and a recessive allele (a) in the population and that the population is at Hardy-Weinberg equilibrium. What is the frequency of heterozygotes in the population?

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Quizplus · Accepted Answer

The frequency of the recessive condition (aa) is q^2 = 1/400 = 0.0025, so q = √0.0025 = 0.05. The frequency of heterozygotes (Aa) is 2pq, where p = 1 - q = 0.95. Therefore, 2pq = 2 * 0.95 * 0.05 = 0.095.

Suppose That in a Population the Frequency of a Particular