You are studying cannibals in Borneo and want to determine if a specific village population is in Hardy-Weinberg equilibrium with respect to the two co-dominant M and N blood type alleles (L^M, L^N) segregating at the single-gene locus. Choose the answer below that gives the correct expected number of M, MN, and N individuals and the critical value to which you will compare your chi-square value (see Table 3.7 for critical values). $\begin{array}{lllc} &&&\underline{ Phenotypes }\ \text { M } & \text { MN } &N& \text { Total \# genotypes } \ 287 & 665 & 123 & 1075 \end{array}$

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The expected number of individuals with each phenotype can be calculated using the Hardy-Weinberg equation:p^2 + 2pq + q^2 = 1where p is the frequency of the M allele and q is the frequency of the N allele.In this case, we are given the number of individuals with each phenotype, so we can use these values to calculate the allele frequencies:p = (287 + 665/2) / 1075 = 0.667q = (665/2 + 123) / 1075 = 0.333Using these allele frequencies, we can calculate the expected number of individuals with each phenotype:M = p^2 * 1075 = 0.667^2 * 1075 = 357MN = 2pq * 1075 = 2 * 0.667 * 0.333 * 1075 = 525N = q^2 * 1075 = 0.333^2 * 1075 = 193The chi-square critical value for a 2x2 contingency table with 1 degree of freedom is 3.814.