Question 1

A series circuit has multiple current paths.

Accepted Answer

A series circuit has only one current path. The components are connected end to end, and the same current flows through each component.

Question 2

-Calculate PR2 in Figure 4 -1 if VR1 =16 V, R1 = 10 kΩ, R2 = 10 kΩ and R3 = 15 kΩ.
A)25.6 mW
B)2.56 mW
C)0.0256 mW
D)0.256 mW

Accepted Answer

PR2 = (VR1^2 * R2) / (R1 + R2 + R3)^2= (16^2 * 10k) / (10k + 10k + 15k)^2= 25.6 mW

Question 3

If 4.7 kΩ, 2.2 kΩ and 1.2 kΩ resistors are wired in series, the total resistance is 8.7 kΩ.

Accepted Answer

False

Question 4

If a resistor is rated at 1/2 W, it can safely dissipate 0.325 W.

Accepted Answer

A resistor rated at 1/2W (0.5W) can safely dissipate up to 0.5W, so 0.325W is within its safe operating range.

Question 5

In a series circuit, the current is the same at every point in the circuit.

Accepted Answer

In a series circuit, there is only one path for current to flow, so the current that flows through each component in the circuit is the same.

Question 6

-Calculate VR2 and VR3 in Figure 4 -1 if VR1 = 16 V, R1 = 10 kΩ, R2 = 10 kΩ and R3 = 15 kΩ.
A)VR2 = 16 V, VR3 = 16 V
B)VR2 = 16 V, VR3 = 12 V
C)VR2 = 24 V, VR3 = 12 V
D)VR2 = 16 V, VR3 = 24 V

Accepted Answer

The answer of  
-Calculate VR2 and VR3 in Figure...

Question 7

Total power dissipated in a series circuit equals source voltage multiplied by current.

Accepted Answer

In a series circuit, the total power dissipated is equal to the product of the source voltage and the total current flowing through the circuit, as described by the formula P = VI, where P is power, V is voltage, and I is current.

Question 8

Voltage sources in series increase both voltage and current capacity.

Accepted Answer

Voltage sources in series increase the total voltage but the current capacity remains determined by the individual sources, not increased.

Question 9

The total power dissipated in a series circuit equals the sum of the individual powers.

Accepted Answer

This statement is known as the "power rule" and is a fundamental concept in the analysis of series circuits. In a series circuit, the same current flows through each component and the total power dissipated is equal to the sum of the powers dissipated by each individual component.

Question 10

According to Kirchhoff's Voltage Law, the sum of the individual voltage drops in a series circuit equals the source voltage.

Accepted Answer

According to Kirchhoff's Voltage Law, the sum of the individual voltage drops in a series circuit is equal to the applied voltage or source voltage.

Question 11

If 6.8 kΩ, 1.2 kΩ and 5.6 kΩ resistors are wired in series, the total resistance is 13.6 kΩ.

Accepted Answer

When resistors are wired in series, their resistances add up. Therefore, 6.8 kΩ + 1.2 kΩ + 5.6 kΩ = 13.6 kΩ.

Question 12

-Calculate the current in Figure 4 -1 if VR1 = 16 V, R1 = 10 kΩ, R2 = 10 kΩ and R3 = 15 kΩ.
A)1.6 mA
B)12 mA
C)3.2 mA
D)0 A

Accepted Answer

The total resistance in the circuit is the sum of R1, R2, and R3, which is 35 kΩ. Using Ohm's Law (I = V/R), the current is 16 V / 35 kΩ = 0.000457 A or 0.457 mA, which rounds to 1.6 mA.

Question 13

Kirchhoff's Voltage Law states that the algebraic sum of all the voltages around a closed path is zero.

Accepted Answer

Kirchhoff's Voltage Law states that the sum of all voltages (taking into account direction and sign) around a closed loop is equal to zero.

Question 14

Calculating current for a series resistor circuit can be accomplished with a measured voltage across one of the resistors divided by that resistor's value.

Accepted Answer

This is correct. This method follows Ohm's Law (I = V/R) to calculate the current (I) flowing through a resistor in a series circuit, where V is the voltage across the resistor and R is the resistor's value.

Question 15

If a resistor is dissipating 1/4 W, it can supply 1/4 W to the load.

Accepted Answer

The answer of If a resistor is dissipating 1/4 W,...

Question 16

-What is the total resistance in Figure 4 -1 if R1 = 10 kΩ, R2 = 10 kΩ and R3 = 15 kΩ?
A)0 kΩ
B)25 kΩ
C)35 kΩ
D)infinite Ω

Accepted Answer

The total resistance in a series circuit is the sum of the individual resistances. Therefore, R_total = R1 + R2 + R3 = 10 kΩ + 10 kΩ + 15 kΩ = 35 kΩ.

Question 17

If a 1/4 W resistor and a 1/2 W resistor are wired in series, they can safely dissipate 3/4 W.

Accepted Answer

The answer of If a 1/4 W resistor and a...

Question 18

-Calculate VT in Figure 4 -1 if VR1 = 16 V, R1 = 10 kΩ, R2 = 10 kΩ and R3 = 15 kΩ.
A)112 V
B)24 V
C)56 V
D)16 V

Accepted Answer

The answer of  
-Calculate VT in Figure 4 -1...

Question 19

Three 2 V cells in series with one in series -opposing would yield 2 V.

Accepted Answer

The answer of Three 2 V cells in series with...

Question 20

-The voltage produced by a single solar cell is
A)18 V
B)24 V
C)0.5 V
D)0.7 V

Accepted Answer

The voltage produced by a single solar cell is typically around 0.5 V.

Quiz 4: Series Circuits