In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of the allele a is 0.3. What is the frequency of individuals that are homozygous for this allele?
A) 0.09
B) 0.49
C) 0.9
D) 9.0

Question

Quizplus · Accepted Answer

In a Hardy-Weinberg population, the frequency of homozygous individuals for an allele can be calculated as the square of the frequency of that allele. Therefore, the frequency of homozygous individuals for allele a would be (0.3)^2 = 0.09.

In a Hardy-Weinberg Population with Two Alleles, a and A