In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. What is the frequency of individuals that are heterozygous for this allele?
A) 0.020
B) 0.04
C) 0.16
D) 0.32

Question

Quizplus · Accepted Answer

The frequency of heterozygous individuals (Aa) is calculated using 2pq, where p is the frequency of allele A and q is the frequency of allele a. Since q = 0.2, p = 1 - q = 0.8. Therefore, 2pq = 2 * 0.8 * 0.2 = 0.32.

In a Hardy-Weinberg Population with Two Alleles, a and A