In the equation relating equilibrium to thermodynamics, a = -RTb,

Question

Quizplus · Accepted Answer

The equation that relates equilibrium to thermodynamics is ∆G = ∆G° + RTlnQ, where Q is the reaction quotient. At equilibrium, ∆G = 0, so 0 = ∆G° + RTlnK, which can be rearranged to a = -RTb, where a = ∆G°/RT and b = 1/T. Thus, a = F1F1F1S1∆F1F1F10G/RT and b = 1/T = F1F1F1S1°F1F1F10. Therefore, the closest option is C, where a = F1F1F1S1∆F1F1F10G F1F1F1S1∆F1F1F10G/F1F1F1S1°F1F1F10 and b = lnK.

In the Equation Relating Equilibrium to Thermodynamics, a = -RTb Δ\DeltaΔ

In the Equation Relating Equilibrium to Thermodynamics, a = -RTb $\Delta$