The table is filled correctly. $$\begin{array} { | l | l | }
\hline \text { Exponential form } & \text { Logarithmic form } \
\hline 8 ^ { - 3 } = 0.001953 & \log _ { 8 } 0.001953 = 3 \
\hline 2 ^ { 0 } = 1 & \log _ { 2 } 1 = 0 \
\hline 0.4 ^ { 4 } = 0.0256 & \log _ { 0.4 } 0.0256 = 4 \
\hline 0.8 ^ { - 3 } = 1.953125 & \log _ { 0.8 } 1.953125 = 3 \
\hline
\end{array}$$

Question

The table is filled correctly. $$\begin{array} { | l | l | } 
\hline \text { Exponential form } & \text { Logarithmic form } \
\hline 8 ^ { - 3 } = 0.001953 & \log _ { 8 } 0.001953 = 3 \
\hline 2 ^ { 0 } = 1 & \log _ { 2 } 1 = 0 \
\hline 0.4 ^ { 4 } = 0.0256 & \log _ { 0.4 } 0.0256 = 4 \
\hline 0.8 ^ { - 3 } = 1.953125 & \log _ { 0.8 } 1.953125 = 3 \
\hline
\end{array}$$

Quizplus · Accepted Answer

The logarithmic form corresponding to $8^{-3} = 0.001953$ should be $\log_{8} 0.001953 = -3$, not $3$.

The Table Is Filled Correctly