Factor the special product: $9 a ^2 - 49$

A) (3a+7)(3a-7)
B) $( 3 a - 7 ) ^ { 2 }$
C) (3a-7)(3a-7)
D) $( 3 a + 7 ) ^ { 2 }$

Name: Factor the special product: $9 a ^2 - 49$ A) (3a+7)(3a-7) B) $( 3 a - 7 ) ^ { 2 }$ C) (3a-7)(3a-7) D) $( 3 a + 7 ) ^ { 2 }$
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Question

Factor the special product: $9 a ^2 - 49$

A) (3a+7)(3a-7) 
B) $( 3 a - 7 ) ^ { 2 }$ 
C) (3a-7)(3a-7) 
D) $( 3 a + 7 ) ^ { 2 }$

Quizplus · Accepted Answer

This is a special product known as a difference of squares. It can be factored as follows:

\begin{align*}
9 a ^2 - 49 &= (3a)^2 - 7^2 \
&= (3a+7)(3a-7)
\end{align*}

Therefore, the best choice is A.

Factor the Special Product 9a2−499 a ^2 - 499a2−49 A) (3a+7)(3a-7) B)

Factor the Special Product $9 a ^2 - 49$ A) (3a+7)(3a-7)
B)