Factor the special product: $16 y ^ { 2 } - 1$
A) (4y +1)(4y - 1)
B) (4y - 1)²
C) (8y +1)(8y - 1)
D) (4y -1)(4y -1)

Question

Factor the special product: $16 y ^ { 2 } - 1$
A) (4y +1)(4y - 1) 
B) (4y - 1)²
C) (8y +1)(8y - 1) 
D) (4y -1)(4y -1)

Quizplus · Accepted Answer

The given expression is in the form of a special product, which is $(a+b)(a-b)=a^2-b^2$. In this case, $a=4y$ and $b=1$. Therefore, using the special product formula, we can write the given expression as $(4y + 1)(4y - 1)=16y^2-1$. Thus, the answer is choice letter A.

Factor the Special Product 16y2−116 y ^ { 2 } - 116y2−1

Factor the Special Product $16 y ^ { 2 } - 1$