Factor completely: $x ^4 - 16$
A) $( x + 2 ) ^ { 2 } ( x - 2 ) ^ { 2 }$
B) $\left( x ^ { 2 } + 4 \right) ( x + 2 ) ( x - 2 )$
C) $( x - 2 ) ^ { 4 }$
D) $\left( x ^ { 2 } - 4 \right) ^ { 2 }$

Question

Quizplus · Accepted Answer

We can use the difference of squares to rewrite the expression as $(x^2)^2 - 4^2$. Then, we factor using the difference of squares again and get $(x^2+4)(x^2-4) = (x^2+4)(x+2)(x-2)$.

Factor Completely x4−16x ^4 - 16x4−16 A) (x+2)2(x−2)2( x + 2 ) ^ { 2 } ( x - 2 ) ^ { 2 }(x+2)2(x−2)2

Factor Completely $x ^4 - 16$ A) $( x + 2 ) ^ { 2 } ( x - 2 ) ^ { 2 }$