Factor: $x ^ { 2 } + 4 x - 12$
A) (x +2)(x-6)
B) (x +4)(x-3)
C) (x-2)(x +6)
D) $4 \left( x ^ { 2 } + x - 3 \right)$

Name: Factor: $x ^ { 2 } + 4 x - 12$ A) (x +2)(x-6) B) (x +4)(x-3) C) (x-2)(x +6) D) $4 \left( x ^ { 2 } + x - 3 \right)$
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Question

Factor: $x ^ { 2 } + 4 x - 12$
A) (x +2)(x-6) 
B) (x +4)(x-3) 
C) (x-2)(x +6) 
D) $4 \left( x ^ { 2 } + x - 3 \right)$

Quizplus · Accepted Answer

The quadratic $x^2 + 4x - 12$ factors into $(x - 2)(x + 6)$ because the product of -2 and 6 is -12 and their sum is 4.

Factor x2+4x−12x ^ { 2 } + 4 x - 12x2+4x−12

Factor $x ^ { 2 } + 4 x - 12$