Factor the special product: $9 x ^ { 2 } + 12 x + 4$
A) $( 3 x - 2 ) ^ { 2 }$
B) $( 3 x + 2 ) ^ { 2 }$
C) $3 \left( 3 x ^ { 2 } - 4 x + 4 \right)$
D) (3x +2)(3x - 2)

Question

Factor the special product: $9 x ^ { 2 } + 12 x + 4$
A) $( 3 x - 2 ) ^ { 2 }$ 
B) $( 3 x + 2 ) ^ { 2 }$ 
C) $3 \left( 3 x ^ { 2 } - 4 x + 4 \right)$
D) (3x +2)(3x - 2)

Quizplus · Accepted Answer

We can see that the first term is a perfect square, which is $3x^2$, and the last term is a perfect square, which is $2^2=4$. Also, the middle term is twice the product of the square roots of the first and last terms, which is $2\cdot 3x\cdot 2 = 12x$. Therefore, we can write the expression as $(3x+2)^2$.

Factor the Special Product 9x2+12x+49 x ^ { 2 } + 12 x + 49x2+12x+4

Factor the Special Product $9 x ^ { 2 } + 12 x + 4$