Factor completely: $$x ^ { 2 } - 5 x - 6$$
A)(x - 2)(x - 3)
B)(x + 2)(x - 3)
C)(x + 1)(x - 6)
D)(x - 1)(x - 6)

Name: Factor completely: \[x ^ { 2 } - 5 x - 6\] A)(x - 2)(x - 3) B)(x + 2)(x - 3) C)(x + 1)(x - 6) D)(x - 1)(x - 6)
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Question

Quizplus · Accepted Answer

The quadratic expression $x^2 - 5x - 6$ can be factored by finding two numbers that multiply to -6 and add to -5. These numbers are 1 and -6, so the factorization is $(x + 1)(x - 6)$.

Factor Completely x2−5x−6x ^ { 2 } - 5 x - 6x2−5x−6

Factor Completely $x ^ { 2 } - 5 x - 6$