What is the momentum in SI units) of a photon of wavelength λ = 560 nm? Planck's constant h = 6.626 × 10^-34 J·s.) A) 3.7 × 10^-42 kg · m/s B) 8.4 × 10^-25 kg · m/s C) 1.2 × 10^-30 kg · m/s D) 1.2 × 10^-27 kg · m/s E) 3.6 × 10^-27 kg · m/s

Question

Quizplus · Accepted Answer

The momentum of a photon can be calculated by dividing its energy by its speed of light. The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. By plugging in the given values, we get:

E = (6.626 × 10^-34 J·s) × (3.00 × 10^8 m/s) / (560 × 10^-9 m)
E = 3.55 × 10^-19 J

The momentum of the photon is then:
p = E/c = (3.55 × 10^-19 J)/(3.00 × 10^8 m/s) = 1.18 × 10^-27 kg · m/s

Therefore, the best choice is D: 1.2 × 10^-27 kg · m/s.

What Is the Momentum in SI Units) of a Photon