An electron m_e = 9.11 × 10^-31 kg) traveling with a velocity of 5.50 × 10⁶ m/s has a de Broglie wavelength of approximately A) 0.0710 nm. B) 0.130 nm. C) 0.180 nm. D) 0.230 nm. E) 0.550 nm.

Question

Quizplus · Accepted Answer

The de Broglie wavelength of an electron is given by λ = h/mv, where h is the Planck constant, m is the mass of the electron, and v is its velocity. Substituting the given values, we get:

λ = h/mv
= 6.626 × 10^-34 J.s / (9.11 × 10^-31 kg) × (5.50 × 10^6 m/s)
≈ 0.130 nm

Therefore, the best choice is B.

An Electron Me = 9

An Electron M_e = 9