An alpha particle has a charge of +2e e = 1.6 × 10^-19 C) and is moving at right angles to a magnetic field B = 0.27 T with a speed v = 6.15 × 10⁵ m/s. The force acting on this charged particle is

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The magnetic force on a charged particle moving perpendicular to a magnetic field is given by F = qvB. For an alpha particle, q = +2e = 2 × 1.6 × 10^-19 C. Substituting the values, F = (2 × 1.6 × 10^-19 C)(6.15 × 10^5 m/s)(0.27 T) = 5.3 × 10^-14 N.

An Alpha Particle Has a Charge of +2e E =