A particle with charge q and mass m moving with speed v in the +x direction enters a magnetic field of strength B pointing in the +y direction. The magnitude of the acceleration of the particle as it travels one semicircle is

Question

Quizplus · Accepted Answer

The correct answer is A because the acceleration of a charged particle in a magnetic field is given by a = qvB/m, where q is the charge of the particle, v is its velocity, B is the magnetic field strength, and m is its mass. As the particle travels in a semicircle, its acceleration is always perpendicular to its velocity, and the magnitude of the acceleration is constant.

A Particle with Charge Q and Mass M Moving with Speed