A capacitor, C₁ = 5.00 ?F, is charged up to 8.00 V. It is then connected to a second uncharged capacitor C₂ = 2.50 ?F. The charge on C₁ after the system has come to equilibrium is

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When the capacitors are connected, the charge will redistribute until the potential difference across each capacitor is the same. The total charge in the system is conserved, so the charge on C1 after the system has come to equilibrium is:Q1 = Q1,initial + Q2,initialQ1 = (5.00 uF)(8.00 V) + (0 uF)(0 V)Q1 = 40.0 uCThe potential difference across each capacitor is:V = Q/CV = 40.0 uC / 7.50 uFV = 5.33 VThe charge on C1 after the system has come to equilibrium is:Q1 = CVQ1 = (5.00 uF)(5.33 V)Q1 = 26.7 uC

A Capacitor, C1 = 5 μ\muμ C B) 13 μ\muμ C C) 20

A Capacitor, C₁ = 5 $\mu$ C
B) 13 $\mu$ C
C) 20