A parallel-plate capacitor has square plates of side 12 cm and a separation of 6.0 mm. A dielectric slab of constant κ = 2.0 has the same area as the plates but has a thickness of 3.0 mm. What is the capacitance of this capacitor with the dielectric slab between its plates?

Question

Quizplus · Accepted Answer

The capacitance of a parallel-plate capacitor with a dielectric is given by C = (ε₀ * κ * A) / d, where ε₀ is the permittivity of free space, κ is the dielectric constant, A is the area of the plates, and d is the separation between the plates. The effective separation is the sum of the dielectric thickness and the remaining air gap. Calculating with given values, the capacitance is approximately 28 pF.

A Parallel-Plate Capacitor Has Square Plates of Side 12 Cm