The capacitance of a parallel-plate capacitor is 24 μF when the plates are separated by a material of dielectric constant 2.0. If this material is removed, leaving air between the plates, and the separation between the plates is tripled, the capacitance is

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Quizplus · Accepted Answer

The original capacitance with the dielectric is 24 μF. Without the dielectric, the capacitance is halved to 12 μF (since the dielectric constant is 2.0). Tripling the separation reduces the capacitance by a factor of 3, resulting in 12 μF / 3 = 4.0 μF.

The Capacitance of a Parallel-Plate Capacitor Is 24 μF When